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主要内容

分段函数的极限

问题

g(x)={ln(x)当 0<x2x2ln(2)当 x>2g(x)=\begin{cases} \text{ln}(x)&\text{当 }0<x\leq2 \\\\ x^2\text{ln}(2)&\text{当 }x>2 \end{cases}
求解 limit, start subscript, x, \to, 2, end subscript, g, left parenthesis, x, right parenthesis.
选出正确答案:
不会做了?
不会做了?